(4x^2-2x+1)+(2x+8)=0

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Solution for (4x^2-2x+1)+(2x+8)=0 equation: 



(4x^2-2x+1)+(2x+8)=0

We get rid of parentheses

4x^2-2x+2x+1+8=0

We add all the numbers together, and all the variables

4x^2+9=0

a = 4; b = 0; c = +9;
Δ = b2-4ac
Δ = 02-4·4·9
Δ = -144
Delta is less than zero, so there is no solution for the equation

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